求两道化学题的解法，，答得好有加分。

1. 假设为1L,则m=1.05kg=1050g     ch3cooh质量为1050x0.995=1044。75，物质的量为1044。75/60=17.4125     消空渗     摩尔浓度c=17.4125/1=17.4125mol/L   

   质量摩尔浓度 b=17.4125/1044.75=0.017mol/g

2. 后面这个条件不足求不了。好像可以，假设为100g  则m（NH3）=28g   n（NH3）=1.65mol

   nh3的质量摩尔拿脊浓度b=1.65/28=0.059      m（H2O）=72g    n（H2O）=4mol   

    摩尔亏旅分数x=1.65/(4+1.65)=0.292

1、
c=n/V，b=n/m
M(HAc)=60g/mol
n(HAc)=m*0.995/60
则b=m*0.995/60/m=0.995/60=0.0166mol/g
V=m/d
则c=m*0.995/60/(m/1050)=17.4mol/L
2、
含NH3质量分数 28% 则含水质量分数 72%
设总质做段量纯坦誉为m
n(NH3)=m*28%/17
n(H2O)=m*72%/信樱18
b(NH3)=m*28%/17/m=0.016
x(NH3)=m*28%/17/(m*28%/17+m*72%/18)=0.29

含NH3质量分数 28% 则含衡悄段水质量分数 72%
设咐誉总质量为m
n(NH3)=m*28%/17
n(H2O)=m*72%/18
b(NH3)=m*28%/17/运亏m=0.016
x(NH3)=m*28%/17/(m*28%/17+m*72%/18)=0.29