由交点(-3,-3)可得出直线方程的表达式为y+3=k*(x+3), 圆心为(0,-2),半径为做渣神5,截得弦长为4根号5,易得圆心到直线距离为根号5,点到直线距离有公式,带入可得k,应该有两个解,我这没笔,纯亏你自己算一下梁者吧
圆心(0,-2),半径5,弦长4√5,由勾股定理得喊知弦心距√5
交点(-3,-3),设L:y+3=m(x+3),即mx-y+3m-3=0
点到直线的距离得世渗举弦心距搜碧=|2+3m-3|/√(m²+1),
|2+3m-3|/√(m²+1)=√5
m=2或-1/2
l:2x-y+3=0或x+2y+9=0
设L:y+3=m(x+3),即mx-y+3m-3=0
弦心裤拦源距=|2+3m-3|/√(m²+1),
|2+3m-3|/√胡态(m²+1)=√5
m=2或-1/2
l2x-y+3=0或衡哪x+2y+9=0