答案为0.95m,设木棍颤笑搏刚到窗框上升旦沿时间为t1,刚好整体离开窗茄祥框时间t2,则有;s=0.5g(t2^2-t1^2)t2-t1=0.4h=0.5gt1^2+0.5s=1.5+0.5联立解得h=0.95m
1.5+0.5=2=1/2*g*((t+0.4)(t+0.4)-t*t)t=0.3h=0.5*g*t*t+0.5=0.95m